[m-dev.] more correctness problems

Peter Stuckey pjs at cs.mu.OZ.AU
Mon Apr 3 10:17:04 AEST 2006

On 03/04/2006, at 9:51 AM, Ralph Becket wrote:

> Peter Stuckey, Monday,  3 April 2006:
>> But a better solution to this is
>> 	member(out(I), in(list(I))  I <= any
>> where it is clear that the any doesnt get instantiated,  To support 
>> this
>> we have to improve the mode analysis for mode variables.
> Can you explain that?  It isn't at all clear to me why the any wouldn't
> be further constrained (e.g., by unification).

The only constraint that touches an any variable which is guaranteed not
to further constraint it are det ones.


	plus(fdint::in(any), fdint::in(any), fdint::out(any)) is det.

The most usual case of this is equality in the right modes.

	fdint::out(any) = fdint::in(any)


:- pred member(fdint::out(any), list(fdint)::in(list(any))) is multi.

member(X, [A|_) :- X = A.
member(X, [_|R]) :- member(X,R).

This is correct for notional mode

- pred member(fdint::out(any), list(fdint)::same(list(any))) is multi.

Actually now I see your question.  How do I know the definition is not

member(X, [Y,Z|_]) :- Y = Z, X = Y.

In HAL we solved this by having an EQ class and doing EQ and SOLVER 

The first version of member does not use EQ, it just uses copying
The second version does (for Y = Z).

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