[mercury-users] Mercury Types Problem
Ralph Becket
rafe at cs.mu.OZ.AU
Thu Jun 20 15:43:08 AEST 2002
Bob McKay, Thursday, 20 June 2002:
> Hi folks; probably a fairly trivial syntax problem this time:
>
> On Tuesday, May 28, 2002, at 02:01 PM, Ralph Becket wrote:
> >Tip: it's a good idea to name complex higher order types and modes:
> >
> >:- type eval_pred(T) == (pred(T, T, message, message, supply, supply)).
> >:- inst eval_pred == (pred(in, uo(individuals), out, out, mdi, muo)
> >is det).
>
> I'm trying this as:
>
> :- type eval_pred(Ind) == (pred(Ind, Ind, message, message, supply,
> supply)).
> :- mode eval_pred == (pred(in, out, out, out, mdi, muo) is det).
>
> :- pred eval_ind(eval_pred(ind)). %1
> :- mode eval_ind(eval_pred). %2
>
>
> eval_ind(Uneval_ind, Eval_ind, Defmessage, Fitmessage, RS0, RS1) :-
> <clause body>
>
> gives the error messages
>
> eval.m:017: Error: no determinism declaration for exported
> eval.m:017: predicate `eval:eval_ind/1'.
This says you've missed off the `is <determinism>' part of the mode
declaration for eval_ind/1.
> eval.m:026: Error: clause for predicate `eval:eval_ind/6'
> eval.m:026: without preceding `pred' declaration.
This says you've written a clause
eval_ind(A, B, C, D, E, F) :- ...
but you've only declared a pred with this name that takes a single
argument:
:- pred eval_ind(eval_pred(ind)).
^^^^^^^^^^^^^^--- one argument.
> eval.m:016: Error: no clauses for predicate `eval:eval_ind/1'.
and you haven't written any eval_ind/1 clauses
> eval.m:026: Inferred :- pred eval_ind((rep:ind), (rep:ind),
> (myutils:message), (
> myutils:message), (random:supply), (random:supply)).
but this is what the compiler managed to infer about the mysterious
eval_ind/6 clause!
- Ralph
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