[mercury-users] Type declaration for a higher order function without arguments?
Peter Hawkins
peter at hawkins.emu.id.au
Fri Aug 6 12:53:26 AEST 2004
Hi...
How does one declare a function type that doesn't take arguments?
This is ok:
:- type myfunc(T) = (impure func(int) = T).
This is not:
:- type myfunc(T) = (impure func = T).
Nor is this:
:- type myfunc(T) = (impure func() = T).
What's the secret?
Thanks,
Peter
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