[mercury-users] inferred determinism

[Michael Day]

Hi,

The compiler infers a determinism of nondet for the predicate foo below,
unless the call to `zero' in the first clause is replaced by the literal
value 0. But it's an output argument, so why should it care? (I wasn't 
sure if this should go to mercury-bugs or mercury-features...)

Michael

:- pred foo(int, list(T)).
:- mode foo(out, in) is det.

foo(zero, []).
foo(N, [_|Xs]) :- foo(N0, Xs), N = N0+1.

:- func zero = int.

zero = 0.


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